Get the names of an XML nodes children.
This is a convenient way to obtain the XML tag name
of each of the sub-nodes of a given
XMLNode object.
## S3 method for class 'XMLNode' names(x)
x |
the |
A character vector returning the
tag names of the sub-nodes of the given
XMLNode argument.
This overrides the regular names method
which would display the names of the internal
fields of an XMLNode object.
Since these are intended to be invisible and
queried via the accessor methods (xmlName,
xmlAttrs, etc.), this should not
be a problem. If you really need the names
of the fields, use names(unclass(x)).
Duncan Temple Lang
doc <- xmlTreeParse(system.file("exampleData", "mtcars.xml", package="XML"))
names(xmlRoot(doc))
r <- xmlRoot(doc)
r[names(r) == "variables"]Please choose more modern alternatives, such as Google Chrome or Mozilla Firefox.