Retrieve the namespace value of an XML node.
Each XML node has a namespace identifier which is a string indicating
in which DTD (Document Type Definition) the definition of that element
can be found. This avoids the problem of having different document
definitions using the same names for XML elements that have different
meaning.
To resolve the name space, i.e.
i.e. find out to where the identifier points,
one can use the
expression xmlNamespace(xmlRoot(doc)).
The class of the result is
is an S3-style object of class XMLNamespace.
xmlNamespace(x) xmlNamespace(x, ...) <- value
x |
the object whose namespace is to be computed |
value |
the prefix for a namespace that is defined in the node or any of the ancestors. |
... |
additional arguments for setting the name space |
For non-root nodes, this returns a string giving the identifier of the name space for this node. For the root node, this returns a list with 2 elements:
id |
the identifier by which other nodes refer to this namespace. |
uri |
the URI or location that defines this namespace. |
local |
? (can't remember off-hand). |
Duncan Temple Lang
doc <- xmlTreeParse(system.file("exampleData", "job.xml", package="XML"))
xmlNamespace(xmlRoot(doc))
xmlNamespace(xmlRoot(doc)[[1]][[1]])
doc <- xmlInternalTreeParse(system.file("exampleData", "job.xml", package="XML"))
# Since the first node, xmlRoot() will skip that, by default.
xmlNamespace(xmlRoot(doc))
xmlNamespace(xmlRoot(doc)[[1]][[1]])
node <- xmlNode("arg", xmlNode("name", "foo"), namespace="R")
xmlNamespace(node)
doc = xmlParse('<top xmlns:r="http://www.r-project.org"><bob><code>a = 1:10</code></bob></top>')
node = xmlRoot(doc)[[1]][[1]]
xmlNamespace(node) = "r"
node
doc = xmlParse('<top xmlns:r="http://www.r-project.org"><bob><code>a = 1:10</code></bob></top>')
node = xmlRoot(doc)[[1]][[1]]
xmlNamespaces(node, set = TRUE) = c(omg = "http://www.omegahat.net")
nodePlease choose more modern alternatives, such as Google Chrome or Mozilla Firefox.