Function hybridize takes two genind in inputs and generates hybrids individuals having one parent in both objects.
The function hybridize
performs hybridization between two set
of genotypes stored in genind objects (referred as the "2
populations"). Allelic frequencies are derived for each population,
and then gametes are sampled following a multinomial distribution.
hybridize( x1, x2, n, pop = "hybrid", res.type = c("genind", "df", "STRUCTURE"), file = NULL, quiet = FALSE, sep = "/", hyb.label = "h" )
x1 |
a genind object |
x2 |
a genind object |
n |
an integer giving the number of hybrids requested |
pop |
a character string giving naming the population of the created hybrids. |
res.type |
a character giving the type of output requested. Must
be "genind" (default), "df" (i.e. data.frame like in
|
file |
a character giving the name of the file to be written when 'res.type' is "STRUCTURE"; if NULL, a the created file is of the form "hybrids\_[the current date].str". |
quiet |
a logical specifying whether the writing to a file (when 'res.type' is "STRUCTURE") should be announced (FALSE, default) or not (TRUE). |
sep |
a character used to separate two alleles |
hyb.label |
a character string used to construct the hybrids labels; by default, "h", which gives labels: "h01", "h02", "h03",... |
The result consists in a set of 'n' genotypes, with different possible outputs (see 'res.type' argument).
If the output is a STRUCTURE file, this file will have the following
caracteristics:
- file contains the genotypes of the parents, and then the genotypes
of hybrids
- the first column identifies genotypes
- the second column identifies the population (1 and 2 for parents x1 and x2;
3 for hybrids)
- the first line contains the names of the markers
- one row = one genotype (onerowperind will be true)
- missing values coded by "-9" (the software's default)
A genind object (by default), or a data.frame of alleles (res.type="df"). No R output if res.type="STRUCTURE" (results written to the specified file).
Thibaut Jombart t.jombart@imperial.ac.uk
## Not run: ## Let's make some cattle hybrids data(microbov) ## first, isolate each breed temp <- seppop(microbov) names(temp) salers <- temp$Salers zebu <- temp$Zebu ## let's make some... Zeblers zebler <- hybridize(salers, zebu, n=40, pop="Zebler") ## now let's merge all data into a single genind newDat <- repool(microbov, zebler) ## make a correspondance analysis ## and see where hybrids are placed X <- genind2genpop(newDat, quiet=TRUE) coa1 <- dudi.coa(tab(X),scannf=FALSE,nf=3) s.label(coa1$li) add.scatter.eig(coa1$eig,2,1,2) ## End(Not run)
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