"label" assignment operator
"label" assignment operator for vectors, dendrogram, and hclust classes.
labels(object, ...) <- value ## Default S3 replacement method: labels(object, ...) <- value ## S3 replacement method for class 'dendrogram' labels(object, ...) <- value ## S3 method for class 'hclust' labels(object, order = TRUE, ...) ## S3 replacement method for class 'hclust' labels(object, ...) <- value ## S3 method for class 'phylo' labels(object, ...) ## S3 replacement method for class 'phylo' labels(object, ...) <- value
object |
a variable name (possibly quoted) who's label are to be updated |
... |
parameters passed (not currently in use) |
value |
a value to be assigned to object's label |
order |
default is FALSE. Only relevant for extracting labels from an hclust object (with labels.hclust). Setting order=TRUE will return labels in their order in the dendrogram, instead of the riginal labels order retained from object$labels - which ususally corresponding to the row or column names of the dist object provided to the hclust function. |
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The updated object
Gavin Simpson, Tal Galili (with some ideas from Gregory Jefferis's dendroextras package)
The functions here are based on code by Gavin and kohske from (adopted to dendrogram by Tal Galili): https://stackoverflow.com/questions/4614223/how-to-have-the-following-work-labelsx-some-value-r-question Also with some ideas from Gregory Jefferis's dendroextras package.
x <- 1:3 labels(x) labels(x) <- letters[1:3] labels(x) # [1] "a" "b" "c" x # a b c # 1 2 3 # get("labels<-") ################ # Example for using the assignment with dendrogram and hclust objects: hc <- hclust(dist(USArrests[1:3, ]), "ave") dend <- as.dendrogram(hc) labels(hc) # "Arizona" "Alabama" "Alaska" labels(hc) <- letters[1:3] labels(hc) # "a" "b" "c" labels(dend) # "Arizona" "Alabama" "Alaska" labels(dend) <- letters[1:3] labels(dend) # "a" "b" "c" suppressWarnings(labels(dend) <- LETTERS[1:2]) # will produce a warning labels(dend) # "A" "B" "A" labels(dend) <- LETTERS[4:6] # will replace the labels correctly # (the fact the tree had duplicate labels will not cause a problem) labels(dend) # "D" "E" "F"
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