order.dendrogram<- assignment operator
order.dendrogram<- assignment operator. This is useful in cases where some object is turned into a dendrogram but its leaves values (the order) are all mixed up.
order.dendrogram(object, ...) <- value
object |
a variable name (possibly quoted) who's label are to be updated |
... |
parameters passed (not currently in use) |
value |
a value to be assigned to object's leaves value (their "order") |
dendrogram with updated order leaves values
################ # Example for using the assignment with dendrogram and hclust objects: hc <- hclust(dist(USArrests[1:4, ]), "ave") dend <- as.dendrogram(hc) str(dend) order.dendrogram(dend) # 4 3 1 2 order.dendrogram(dend) <- 1:4 order.dendrogram(dend) # 1 2 3 4 str(dend) # the structure is still fine. # This function is very useful if we try playing with subtrees # For example: hc <- hclust(dist(USArrests[1:6, ]), "ave") dend <- as.dendrogram(hc) sub_dend <- dend[[1]] order.dendrogram(sub_dend) # 4 6 # now using as.hclust(sub_dend) will cause trouble: # labels(as.hclust(sub_dend)) # As of R 3.1.1-patched - this will produce an Error (as it should) :) # let's fix it: order.dendrogram(sub_dend) <- rank(order.dendrogram(sub_dend), ties.method = "first") labels(as.hclust(sub_dend)) # We now have labels :)
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