Compute the exact length of a time span
Compute the exact length of a time span
time_length(x, unit = "second") ## S4 method for signature 'Interval' time_length(x, unit = "second")
x |
a duration, period, difftime or interval |
unit |
a character string that specifies with time units to use |
When x is an Interval object and
unit are years or months, time_length() takes into account
the fact that all months and years don't have the same number of days.
When x is a Duration, Period
or difftime() object, length in months or years is based on their
most common lengths in seconds (see timespan()).
the length of the interval in the specified unit. A negative number connotes a negative interval or duration
int <- interval(ymd("1980-01-01"), ymd("2014-09-18"))
time_length(int, "week")
# Exact age
time_length(int, "year")
# Age at last anniversary
trunc(time_length(int, "year"))
# Example of difference between intervals and durations
int <- interval(ymd("1900-01-01"), ymd("1999-12-31"))
time_length(int, "year")
time_length(as.duration(int), "year")Please choose more modern alternatives, such as Google Chrome or Mozilla Firefox.