Apply a function to array element indices
Given a function f()
that takes a vector of indices, and an
array of arbitrary dimensions, apply f()
to the elements of a
do.index(a, f, ...)
a |
Array |
f |
Function that takes a vector argument of the same length as
|
... |
Further arguments supplied to |
Returns a matrix of the same dimensions as a
Tamas Papp suggests the one-liner
function(a, f, ...){array(apply(as.matrix(expand.grid(lapply(dim(a),seq_len),KEEP.OUT.ATTRS=FALSE)),1,f,...),dim(a))}
which is functionally identical to do.index()
; but
it is no faster than the version implemented in the package, and (IMO)
is harder to read.
Further note that function arow()
is much much faster than
do.index()
; it is often possible to rephrase a call to
do.index()
as a call to arow()
; do this where possible
unless the additional code opacity outweighs the speed savings.
Robin K. S. Hankin, with improvements by Gabor Grothendieck and Martin Maechler, via the R help list
a <- array(0,c(2,3,4)) b <- array(rpois(60,1),c(3,4,5)) f1 <- function(x){sum(x)} f2 <- function(x){sum((x-1)^2)} f3 <- function(x){b[t(x)]} f4 <- function(x){sum(x)%%2} f5 <- function(x,u){x[u]} do.index(a,f1) # should match arow(a,1)+arow(a,2)+arow(a,3) do.index(a,f2) do.index(a,f3) # same as apltake(b,dim(a)) do.index(a,f4) # Male/female toilets at NOC do.index(a,f5,2) # same as arow(a,2)
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