does a vector have the sum required to be a row or column of a magic square?
Returns TRUE if and only if sum(vec)==magic.constant(n,d=d))
is.ok(vec, n=length(vec), d=2)
vec |
Vector to be tested |
n |
Order of square or hypercube. Default assumes order is equal
to length of |
d |
Dimension of square or hypercube. Default of 2 corresponds to a square |
Robin K. S. Hankin
is.ok(magic(5)[1,])
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