Convert “Numeric” Dates
Daten der Form 8710230920 aufspalten in Jahr, Monat, Tag, Std, Min
u.datumdecode(d, YMDHMnames = c("Jahr", "Monat", "Tag", "Std", "Min"))d |
numeric dates in the form YYMMDDHHMM. |
YMDHMnames |
(column) names to be used for the result. |
a numeric matrix (or vector) with 5 columns containing the year, month, etc.
MM: This is a wrong concept, and also suffers from the “millenium bug” (by using only 2 digits for the year).
?? (someone at SfS ETH)
R's proper date-time coding: DateTimeClasses;
u.date etc.
u.datumdecode(8710230920) ## Jahr Monat Tag Std Min ## 87 10 23 9 20 u.datumdecode(c(8710230900, 9710230920, 0210230920)) ## Jahr Monat Tag Std Min ## [1,] 87 10 23 9 00 ## [2,] 97 10 23 9 20 ## [3,] 2 10 23 9 20
Please choose more modern alternatives, such as Google Chrome or Mozilla Firefox.