Extract or Replace Subset of Hyperframe
Extract or replace a subset of a hyperframe.
## S3 method for class 'hyperframe' x[i, j, drop, strip=drop, ...] ## S3 replacement method for class 'hyperframe' x[i, j] <- value ## S3 method for class 'hyperframe' x$name ## S3 replacement method for class 'hyperframe' x$name <- value
x |
A hyperframe (object of class |
i,j |
Row and column indices. |
drop,strip |
Logical values indicating what to do when the hyperframe has only one row or column. See Details. |
... |
Ignored. |
name |
Name of a column of the hyperframe. |
value |
Replacement value for the subset. A hyperframe or (if the subset is a single column) a list or an atomic vector. |
These functions extract a designated subset of a hyperframe, or replace the designated subset with another hyperframe.
The function [.hyperframe is a method for the subset operator
[ for the
class "hyperframe". It extracts the subset of x
specified by the row index i and column index j.
The argument drop determines whether the array structure
will be discarded if possible. The argument strip determines
whether the list structure in a row or column or cell will be discarded if
possible.
If drop=FALSE (the default), the return value is always
a hyperframe or data frame.
If drop=TRUE, and if the selected subset has only one row,
or only one column, or both, then
if strip=FALSE, the result is a
list, with one entry for each array cell that was selected.
if strip=TRUE,
if the subset has one row containing several columns, the result is a list or (if possible) an atomic vector;
if the subset has one column containing several rows, the result is a list or (if possible) an atomic vector;
if the subset has exactly one row and exactly one column, the result is the object (or atomic value) contained in this row and column.
The function [<-.hyperframe is a method for the
subset replacement operator [<- for the
class "hyperframe". It replaces the designated
subset with the hyperframe value.
The subset of x to be replaced is designated by
the arguments i and j as above.
The replacement value should be a hyperframe with the
appropriate dimensions, or (if the specified subset is a single
column) a list of the appropriate length.
The function $.hyperframe is a method for $
for hyperframes. It extracts the relevant column of the hyperframe.
The result is always a list (i.e. equivalent to using
[.hyperframe with strip=FALSE).
The function $<-.hyperframe is a method for $<-
for hyperframes. It replaces the relevant column of the hyperframe.
The replacement value should be a list of the appropriate length.
A hyperframe (of class "hyperframe").
Adrian Baddeley Adrian.Baddeley@curtin.edu.au, Rolf Turner r.turner@auckland.ac.nz and Ege Rubak rubak@math.aau.dk
h <- hyperframe(X=list(square(1), square(2)), Y=list(sin, cos)) h h[1, ] h[1, ,drop=TRUE] h[ , 1] h[ , 1, drop=TRUE] h[1,1] h[1,1,drop=TRUE] h[1,1,drop=TRUE,strip=FALSE] h[1,1] <- list(square(3)) # extract column h$X # replace existing column h$Y <- list(cells, cells) # add new column h$Z <- list(cells, cells)
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