Check Whether Points Have Close Neighbours
For each point in a point pattern, determine whether the point has a close neighbour in the same pattern.
has.close(X, r, Y=NULL, ...) ## Default S3 method: has.close(X,r, Y=NULL, ..., periodic=FALSE) ## S3 method for class 'ppp' has.close(X,r, Y=NULL, ..., periodic=FALSE, sorted=FALSE) ## S3 method for class 'pp3' has.close(X,r, Y=NULL, ..., periodic=FALSE, sorted=FALSE)
X,Y |
Point patterns of class |
r |
Threshold distance: a number greater than zero. |
periodic |
Logical value indicating whether to measure distances in the periodic sense, so that opposite sides of the (rectangular) window are treated as identical. |
sorted |
Logical value, indicating whether the points of |
... |
Other arguments are ignored. |
This is simply a faster version of (nndist(X) <= r)
or (nncross(X,Y,what="dist") <= r).
has.close(X,r) determines, for each point in the pattern X,
whether or not this point has a neighbour in the same pattern X
which lies at a distance less than or equal to r.
has.close(X,r,Y) determines, for each point in the pattern X,
whether or not this point has a neighbour in the other pattern
Y which lies at a distance less than or equal to r.
The function has.close is generic, with methods for
"ppp" and "pp3" and a default method.
A logical vector, with one entry for each point of X.
Adrian Baddeley Adrian.Baddeley@curtin.edu.au.
has.close(redwood, 0.05) with(split(amacrine), has.close(on, 0.05, off)) with(osteo, sum(has.close(pts, 20)))
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