Minimization of a function by the subplex algorithm
subplex
minimizes a function.
subplex(par, fn, control = list(), hessian = FALSE, ...)
par |
Initial guess of the parameters to be optimized over. |
fn |
The function to be minimized. Its first argument must be the vector of parameters to be optimized over. It should return a scalar result. |
control |
A list of control parameters, consisting of some or all of the following:
|
hessian |
If |
... |
Additional arguments to be passed to the function |
The convergence codes are as follows:
invalid input
number of function evaluations needed exceeds maxnfe
success: tolerance tol
satisfied
limit of machine precision reached
For more details, see the source code.
subplex
returns a list containing the following:
par |
Estimated parameters that minimize the function. |
value |
Minimized value of the function. |
count |
Number of function evaluations required. |
convergence |
Convergence code (see Details). |
message |
A character string giving a diagnostic message from the optimizer, or 'NULL'. |
hessian |
Hessian matrix. |
Aaron A. King kingaa@umich.edu
T. Rowan, “Functional Stability Analysis of Numerical Algorithms”, Ph.D. thesis, Department of Computer Sciences, University of Texas at Austin, 1990.
rosen <- function (x) { ## Rosenbrock Banana function x1 <- x[1] x2 <- x[2] 100*(x2-x1*x1)^2+(1-x1)^2 } subplex(par=c(11,-33),fn=rosen) rosen2 <- function (x) { X <- matrix(x,ncol=2) sum(apply(X,1,rosen)) } subplex(par=c(-33,11,14,9,0,12),fn=rosen2,control=list(maxit=30000)) ## compare with optim: optim(par=c(-33,11,14,9,0,12),fn=rosen2,control=list(maxit=30000)) ripple <- function (x) { r <- sqrt(sum(x^2)) 1-exp(-r^2)*cos(10*r)^2 } subplex(par=c(1),fn=ripple,hessian=TRUE) subplex(par=c(0.1,3),fn=ripple,hessian=TRUE) subplex(par=c(0.1,3,2),fn=ripple,hessian=TRUE) rosen <- function (x, g = 0, h = 0) { ## Rosenbrock Banana function (using names) x1 <- x['a'] x2 <- x['b']-h 100*(x2-x1*x1)^2+(1-x1)^2+g } subplex(par=c(b=11,a=-33),fn=rosen,h=22,control=list(abstol=1e-9,parscale=5),hessian=TRUE)
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