Computes the Tau squared coefficient for a multivariate linear hypothesis
Computes the Tau squared index of "effect magnitude". The maximization of this criterion is equivalent to the minimization of Wilk's lambda statistic.
tau2.coef(mat, H, r, indices, tolval=10*.Machine$double.eps, tolsym=1000*.Machine$double.eps)
mat |
the Variance or Total sums of squares and products matrix for the full data set. |
H |
the Effect description sums of squares and products matrix (defined in the same way as the |
r |
the Expected rank of the H matrix. See the |
indices |
a numerical vector, matrix or 3-d array of integers giving the indices of the variables in the subset. If a matrix is specified, each row is taken to represent a different k-variable subset. If a 3-d array is given, it is assumed that the third dimension corresponds to different cardinalities. |
tolval |
the tolerance level to be used in checks for
ill-conditioning and positive-definiteness of the 'total' and
'effects' (H) matrices. Values smaller than |
tolsym |
the tolerance level for symmetry of the
covariance/correlation/total matrix and for the effects ( |
Different kinds of statistical methodologies are considered within the framework, of a multivariate linear model:
X = A B + U
where X is the (nxp) data matrix of original variables, A is a known (nxp) design matrix, B an (qxp) matrix of unknown parameters and U an (nxp) matrix of residual vectors. The τ^2 index is related to the traditional test statistic (Wilk's lambda statistic) and measures the contribution of each subset to an Effect characterized by the violation of a linear hypothesis of the form C B = 0, where C is a known cofficient matrix of rank r. The Wilk's lambda statistic (λ) is given by:
Λ = det(E)/det(T)
where E is the Error matrix and T is the Total matrix. The index τ^2 is related to the Wilk's lambda statistic (Λ) by:
τ^2 = 1 - λ^{(1/r)}
where r is the rank of H the Effect matrix.
The value of the tau2 coefficient.
## --------------------------------------------------------------- ## 1) A Linear Discriminant Analysis example with a very small data set. ## We considered the Iris data and three groups, ## defined by species (setosa, versicolor and virginica). data(iris) irisHmat <- ldaHmat(iris[1:4],iris$Species) tau2.coef(irisHmat$mat,H=irisHmat$H,r=2,c(1,3)) ## [1] 0.8003044 ## --------------------------------------------------------------- ## 2) An example computing the value of the tau_2 criterion for two ## subsets produced when the anneal function attempted to optimize ## the xi_2 criterion (using an absurdly small number of iterations). xiresults<-anneal(irisHmat$mat,2,nsol=2,niter=2,criterion="xi2", H=irisHmat$H,r=2) tau2.coef(irisHmat$mat,H=irisHmat$H,r=2,xiresults$subsets) ## Card.2 ##Solution 1 0.8079476 ##Solution 2 0.7907710 ## ---------------------------------------------------------------
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